Will operator fusion in Relax perform the following fusion? Let me illustrate it with a diagram.
Merge different branch with same starting op.
|---> B --> D ...
A --->
|---> C --> E ...
The B and C have same call.op, call.args, call.attr, can be merged as:
|---> D ...
A ---> B --->
|---> E ...
I think this is a very classic fusion pattern, yet it wasn’t fused in my subgraph, which puzzles me. Or perhaps this fusion is handled in a specific pass that I didn’t invoke?